Behemoth with advanced climate engeneer module 120*5 per each to terraformation. That makes 120x5 =600 per each.

1B can terraform standart (2000) planet in 4 turns. 2000/600=3.33. That is I understand

2B can terraform standart planet in 3 turns. 2000/1200=1.66 less than 2. Error! 

3B can terraform standart planet in 2 turns. 2000/1800=1.11. Ok.

4B can terraform standart planet in 2 turns. 2000/2400=0.83 less than 1. Error!

So. where my math is wrong or why 4x600-Behemoths with 2400 industry can not terraform one 2000-cost planet in one turn? 

Reproduce: go to system galtur. There is 4 such behemoth. and arid planet that could be terraformed to jungle.

System: 

Win7x64. Core i5 4.3 GHz. 16gb RAM. SSD. 

Save: 

UC-10.sav

Diagnostics 195 mb:

https://anonfile.com/zf8fYfo2o8/Diagnostics_-_2020_04_13_1322_54_zip

Sublustris wrote:

I think Terraformation takes round number of turns + 1 turn.

1B can terraform standart (2000) planet in 4 turns. 2000/600=3.33+1=4.33, round up = 5! but not 4 as it is.

That would be too easy. No, no, no - the equation is much trickier, bro :)

Salterius wrote:

Looked through XMLs, the action has a line 'SecondaryFleetProductionMultiplier="0.5"'. So I guess if its two identical behemoths its 1.5x production towards terraforming instead of 2x?

Thank you very much for help! That`s explains everything. Then 6 max-Behemoths = 600+300*5=2100 industry.

 Just tested it in the game - 6 max-Behemoths terraform 2000-planet in 1 turn! Cool! 

And you know Sublustris, you are stealing the bread from Amplitude support service! They owe you now ))))

Well, then I just don`t understand one thing - what is the reason of making in the game multipliers hidden from common players, who can not dig into the game files.